1.委托的定义
internal delegate int MyAddFunDe(int a,int b)
2.匿名方法
1)
MyAddFunDe fun = delegate(int a,int b)
{
return a+b;
}
2)lambda
MyAddFunDe fun = (int a,int b) =>
{
return a+b;
}
3)简洁版
MyAddFunDe fun = (a,b) => a+b;
1.委托的定义
internal delegate int MyAddFunDe(int a,int b)
2.匿名方法
1)
MyAddFunDe fun = delegate(int a,int b)
{
return a+b;
}
2)lambda
MyAddFunDe fun = (int a,int b) =>
{
return a+b;
}
3)简洁版
MyAddFunDe fun = (a,b) => a+b;