LeetCode 202. Happy Number (快乐数字)

Write an algorithm to determine if a number is "happy".

A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.

Example: 19 is a happy number

  • 12 + 92 = 82
  • 82 + 22 = 68
  • 62 + 82 = 100
  • 12 + 02 + 02 = 1

 题目标签:Hash Table

  题目给了我们一个数字,让我们判断它是不是 Happy Number。

  Happy Number 最终会变成1,很好判断;Non-Happy Number 最后会无限循环在一个cycle。

  所以,我们要解决如何判断 一个数字是否在一个无限循环里,可以建立HashSet 记录它每一次的变化数字,一旦它重复了,说明,它在循环。

Java Solution:

Runtime beats 61.14% 

完成日期:05/16/2017

关键词:HashSet

关键点:利用HashSet 记录每一个数字

 1 class Solution 
 2 {
 3     public boolean isHappy(int n) 
 4     {
 5         HashSet<Integer> set = new HashSet<>();
 6         
 7         while(n != 1) // happy number will get out of this loop
 8         {
 9             if(set.contains(n)) // if a number repeats in a cycle, return false;
10                 return false;
11             
12             set.add(n);
13             
14             int sum = 0;
15             
16             while(n != 0) // get each digit from number
17             {
18                 int digit = n % 10;
19                 
20                 sum += digit * digit;
21                 n = n / 10;
22             }
23             
24             n = sum; // update n with new number
25         }
26         
27         return true;
28     }
29 }

参考资料:N/A

LeetCode 题目列表 - LeetCode Questions List

原文地址:https://www.cnblogs.com/jimmycheng/p/7734854.html