hrbustoj 2283 heap解题报告

这是我们校赛的一道题,给一个字符串,判断这是字符串描绘的是不是一个堆,并不难,只是一个简单的模拟,但是也稍微有点麻烦,最起码我的方法代码量比较大,主要用栈做一个父亲与儿子的位置匹配,匹配的方法应该有很多.然后在读入的时候注意数字的读入方法,我一开始只读入了一个数导致出错,后来才改对的

#include<iostream>
#include<cstring>
#include<cstdio>
#include<cmath>
#include<stack>
using namespace std;
#define INF 0x3f3f3f3f
struct NODE
{
    int num;
    int lc,rc;
};
NODE node[22000];
int match[22000],tot,len;
char str[22000];
bool is_a_int(char a);
bool is_a_father(int id,int number)
{
    node[tot].num = number;
    if(str[id+2] == ':')
    {
        return true;
    }
    else
    {
        node[tot].lc = node[tot].rc = INF;
        return false;
    }
}
void find_child(int id)
{
    int start,length,now,end,cnt,number;
    if(str[id+3] == '[')
    {
        start = id+5,length = 0,now = start,end;
        while(is_a_int(str[now]) && is_a_int(str[now+1]))
        {
            length++;
            now++;
        }
        cnt = 0,number = 0;
        end = start + length;
        while(cnt <= length)
        {
            number += pow(10,cnt) * (str[end-cnt] - '0');
            cnt++;
        }
        node[tot].lc = number;
    }
    else if(str[id+3] == '(')
    {
        if(!is_a_int(str[id+4]))
            node[tot].lc = INF;
        else
        {
            start = id+4,length = 0,now = start,end;
            while(is_a_int(str[now]) && is_a_int(str[now+1]))
            {
                length++;
                now++;
            }
            cnt = 0,number = 0;
            end = start + length;
            while(cnt <= length)
            {
                number += pow(10,cnt) * (str[end-cnt] - '0');
                cnt++;
            }
            node[tot].lc = number;
        }
    }
    int douhao_id = match[id+2];
    if(str[douhao_id+1] == '(' && str[douhao_id+2] == ')')
        node[tot].rc = INF;
    else if(is_a_int(str[douhao_id+2]))
    {
        start = douhao_id+2,length = 0,now = start,end;
        while(is_a_int(str[now]) && is_a_int(str[now+1]) )
        {
            length++;
            now++;
        }
        cnt = 0,number = 0;
        end = start + length;
        while(cnt <= length)
        {
            number += pow(10,cnt) * (str[end-cnt] - '0');
            cnt++;
        }
        node[tot].rc = number;
    }
    else if(str[douhao_id+1] == '[')
    {
        start = douhao_id+3,length = 0,now = start,end;
        while(is_a_int(str[now]) && is_a_int(str[now+1]) )
        {
            length++;
            now++;
        }
        cnt = 0,number = 0;
        end = start + length;
        while(cnt <= length)
        {
            number += pow(10,cnt) * (str[end-cnt] - '0');
            cnt++;
        }
        node[tot].rc = number;
    }
}
bool is_a_int(char a)
{
    if(a >= '0' && a <= '9')
        return true;
    else return false;
}
int main()
{
    int t;
    cin>>t;
    while(t--)
    {
        cin>>str;
        stack<int> s;
        while(!s.empty()) s.pop();
        int len = strlen(str);
        memset(match,0,sizeof(match));
        for(int i = 0; i < len; i++)
        {
            if(str[i] == ':')
                s.push(i);
            else if(str[i] == ',')
            {
                match[s.top()] = i;
                s.pop();
            }
        }
        tot = 0;
        for(int i = 0; i < len-1; i++)
        {
            if(is_a_int(str[i]))
            {
                int start_id = i,length = 0;
                int now_id = start_id;
                while(is_a_int(str[now_id]) && is_a_int(str[now_id + 1]) )
                {
                    length++;
                    now_id++;
                }
                int end_id = start_id + length;
                int cnt = 0,number = 0;
                while(cnt <= length)
                {
                    number += pow(10,cnt) * (str[end_id - cnt] - '0');
                    cnt++;
                }
                ///cout<<number<<endl;
                bool flag = is_a_father(end_id,number);
                if(flag)
                {
                    find_child(end_id);
                }
                tot++;
                i += length;
            }
        }
        /*for(int i = 0; i < tot; i++)
        {
            cout<<node[i].num<<endl;
            cout<<node[i].lc<<" "<<node[i].rc<<endl;
        }*/
        bool flag1 = true;
        for(int i = 0; i < tot; i++)
        {
            if(node[i].lc != INF && node[i].num < node[i].lc)
            {
                flag1 = false;
                break;
            }
            if(node[i].rc != INF && node[i].num < node[i].rc)
            {
                flag1 = false;
                break;
            }
        }
        bool flag2 = true;
        for(int i = 0; i < tot; i++)
        {
            if(node[i].lc != INF && node[i].num > node[i].lc)
            {
                flag2 = false;
                break;
            }
            if(node[i].rc != -INF && node[i].num > node[i].rc)
            {
                flag2 = false;
                break;
            }
        }
        if(flag1 || flag2)
            puts("Yes");
        else puts("No");
    }
    return 0;
}
原文地址:https://www.cnblogs.com/jifahu/p/5449037.html