从上到下按层打印二叉树,同一层结点从左至右输出。每一层输出一行

思路:递归,扩容

增加一个deep参数,内部list数量与deep相同,每个深度对应一个list

根节点添加到list(deep-1),然后分别对其左右子树递归求每层的节点,深度每到一个孩子+1

import java.util.ArrayList;


/*
public class TreeNode {
    int val = 0;
    TreeNode left = null;
    TreeNode right = null;

    public TreeNode(int val) {
        this.val = val;

    }

}
*/
public class Solution {
    ArrayList<ArrayList<Integer> > Print(TreeNode pRoot) {
        ArrayList<ArrayList<Integer>> list=new ArrayList<>();
        depth(pRoot,1,list);
        return list;
    }
        public void depth(TreeNode root,int deep,ArrayList<ArrayList<Integer>> list){
        if(root==null){
            return;
        }
        if(deep>list.size()){
            list.add(new ArrayList<>());
        }
        list.get(deep-1).add(root.val);
        depth(root.left,deep+1,list);
        depth(root.right,deep+1,list);
    }
    
}
原文地址:https://www.cnblogs.com/jieyi/p/13380026.html