两数之和

题目描述:

给出一个整数数组,请在数组中找出两个加起来等于目标值的数,
你给出的函数twoSum 需要返回这两个数字的下标(index1,index2),需要满足 index1 小于index2.。注意:下标是从1开始的
假设给出的数组中只存在唯一解
例如:

给出的数组为 {20, 70, 110, 150},目标值为90
输出 index1=1, index2=2

 
输入: [3,2,4],6
返回值: [2,3]
1
import java.util.*;


public class Solution {
    /**
     * 
     * @param numbers int整型一维数组 
     * @param target int整型 
     * @return int整型一维数组
     */
    public int[] twoSum (int[] numbers, int target) {
        
        // write code here
        int[] result = {-1,-1};
        int len = numbers.length;
        for (int i=0; i<len;i++){
            System.out.println("i_numbers:"+i);
            for (int j=0;j<len;j++){
                System.out.println("j_numbers:"+j);
                if (numbers[i] + numbers[j] == target && i<j){
//                     System.out.println("i_numbers:"+numbers[i] + ",j_numbers:"+numbers[j]);
                    result[0] = i+1;
                    result[1] = j+1;
                }
            }
        } 
//         System.out.println(Arrays.toString(result));
        return result;
    }
}

2

import java.util.*;
public class Solution {
    public int[] twoSum(int[] numbers, int target) {
        int[] res  = new int[]{-1,-1};
 
        HashMap<Integer, Integer> map = new HashMap<>();
        for (int i = 0; i < numbers.length; i++) {
            map.put(numbers[i] , i);
        }
 
        for (int i = 0; i < numbers.length; i++) {
            int two = target - numbers[i];
            if (map.containsKey(two) && target != 2*two){
                res[0] = i < map.get(two) ? i  + 1 : map.get(two) + 1 ;
                res[1] = i > map.get(two) ? i  + 1 : map.get(two) + 1;
            }
        }
        return res;
    }
}
原文地址:https://www.cnblogs.com/jieran/p/14709254.html