HDU 1171

母函数简单题

 1 #include <iostream>
 2 #include <cstdio>
 3 using namespace std;
 4 
 5 const int MAX=130000;
 6 int c1[MAX],c2[MAX];
 7 
 8 struct {
 9     int val,num;
10 }thing[55];
11 int n;
12 
13 int main(){
14     while(scanf("%d",&n)!=EOF){
15         if(n<0) break;
16         int sum=0,tmp;
17         for(int i=1;i<=n;i++){
18             scanf("%d%d",&thing[i].val,&thing[i].num);
19             sum+=(thing[i].val*thing[i].num);
20         }
21         tmp=sum/2;
22         for(int i=0;i<=tmp;i++)
23         c1[i]=c2[i]=0;
24         for(int i=0,k=0; i<=tmp&&k<=thing[1].num; i+=thing[1].val,k++)
25         c1[i]=1;
26         for(int i=2;i<=n;i++){
27             for(int j=0;j<=tmp; j++){
28                 if(c1[j]>=1){
29                     for(int k=0,p=0; k+j<=tmp&&p<=thing[i].num; k+=thing[i].val,p++){
30                         c2[j+k]+=c1[j];
31                     }
32                 }
33             }
34             for(int j=0;j<=tmp;j++){
35                 c1[j]=c2[j]; c2[j]=0;
36             }
37         }
38         for(int i=tmp;i>=0;i--){
39             if(c1[i]){
40                 printf("%d %d
",sum-i,i);
41                 break;
42             }
43         }
44     }
45     return 0;
46 }
View Code
原文地址:https://www.cnblogs.com/jie-dcai/p/3796820.html