检索树算法

树结构例如以下所看到的:


要求:需依照属性检索出当中一个树节点并返回值。

思路:

        List<IntPtr> ptrList = new List<IntPtr>();
        IntPtr getEidtPtr(IntPtr fatherPtr)
        {
            if(fathrPtr 中包括目标子节点)
                    return editPtr;
                else
                {
                    if (假设节点存在下一级节点)
                    {
                        ptrList.Add(nextPtr);
                        return getEidtPtr(nextPtr);
                    }
                    else
                    {
                        ptrList.Remove(fatherPtr);
                        if (假设fatherPtr存在同级节点)
                        {
                            ptrList.Add(standPtr);
                            return getEidtPtr(standPtr);
                        }
                        else
                        {
                            if (ptrList.Count == 0)
                                return IntPtr.Zero;
                            else
                            {
                                IntPtr f = getUpPtr();
                                return  getEidtPtr(f);
                            }
                        }
                    }
                }
           
        }


        IntPtr getUpPtr()
        {
            IntPtr fatherPtr1 = ptrList[ptrList.Count - 1];
            ptrList.Remove(fatherPtr1);
            IntPtr stand =得到fatherPtr1的同级节点;
            if (stand != IntPtr.Zero)
                return stand;
            else
                return  getUpPtr();
        }
原文地址:https://www.cnblogs.com/jhcelue/p/7356047.html