Codeforces Round #318 (Div. 2) C Bear and Poker (数学)

简单题,求一下所有数的2和3的幂是任意调整的,把2和3的因子除掉以后必须相等。

求lcm,爆了long long。我得好好反省一下,对连乘不敏感

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;

const int maxn = 1e5+5;
ll a[maxn];


int main()
{
    //freopen("in.txt","r",stdin);
    int n;
    scanf("%d",&n);
    for(int i = 0; i < n; i++){
        scanf("%I64d",a+i);
        while(a[i]%2 == 0) a[i]/=2;
        while(a[i]%3 == 0) a[i]/=3;
    }
    for(int i = 1; i < n; i++){
        if(a[i]!=a[i-1]) {
            puts("NO"); return 0;
        }
    }
    puts("YES");
    return 0;
}
原文地址:https://www.cnblogs.com/jerryRey/p/4770260.html