10405 Longest Common Subsequence

描述:要命的题,回车也算字符,只要是字符就要算才行,绝不能用scanf读取字符串
#include <cstdio>
#include <cstring>
#define N 1010
char str[N],s[N];
int num[N][N];
int main()
{
  //  freopen("a.txt","r",stdin);
    while(gets(str))
    {
        gets(s);
        memset(num,0,sizeof(num));
        int len=strlen(str),count=strlen(s);
        for(int i=len-1; i>=0; i--)
            for(int j=count-1; j>=0; j--)
                if(str[i]==s[j]) num[i][j]=num[i+1][j+1]+1;
                else num[i][j]=num[i+1][j]>num[i][j+1] ? num[i+1][j] : num[i][j+1];
        printf("%d\n",num[0][0]);
    }
    return 0;
}


原文地址:https://www.cnblogs.com/javawebsoa/p/2999566.html