PHP面试题:如何算出两个文件的相对路径

  写一个函数,算出两个文件的相对路径,如:
  $a = ‘/a/b/c/d/e.php’;
  $b =’/a/b/12/34/c.php’;
  <?php
  $a = '/a/b/c/d/e.php';
  $b ='/a/b/12/34/c.php';
  $path1 = explode('/',dirname($a));
  $path2 = explode('/',dirname($b));
  $aLen = count($path1);
  $bLen = count($path2);
  $maxLen = max($aLen,$bLen);
  for($i = 1; $i < $maxLen; $i++){
  if($path1[$i] != $path2[$i] && isset($path1[$i])){
  if(isset($path2[$i]))$bUrl[]=$path2[$i];
  $path .= "../";
  }else{
  $bUrl[]=$path2[$i];
  }
  }
  echo $path.implode('/',$bUrl).'/'.basename($b);
  ?>

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原文地址:https://www.cnblogs.com/javaitpx/p/2862898.html