梯形法求定积分(二)设计一个函数模板,独立的非成员函

/*设计梯形法求定积分的函数模板,这个方法比之前的那个设计求积分的类要思路简单得多,
而且我个人认为这么想更顺*/
#include<iostream>
#include<cmath>
using namespace std;
class Mysin{
public:
 double fun(double x)
 {
  return (sin(x));
 }
};
class F1{
public:
 double fun(double x)
 {
  return (1+x+2*x*x);
 }
};
class F2{
public:
 double fun(double x)
 {
  return (1+x+2*x*x+3*x*x*x);
 }
};


template<class T>
double JiFenHanShu(T cf,double a,double b,int n)
{
 double h,result=0;
 h=(b-a)/n;
 result += (cf.fun(a)+cf.fun(b))/2;
 for(int i=1;i<n;i++)
  result += cf.fun(a+i*h);
 result *= h;
 return result;
}
void main()
{
 Mysin f1;
 F1 f2;
 F2 f3;
 double jieguo1;
 double jieguo2;
 double jieguo3;
 jieguo1=JiFenHanShu(f1,0.0,3.0,1000);
 cout<<"函数f1的定积分值是:"<<jieguo1<<endl;
 jieguo2=JiFenHanShu(f2,0.0,3.0,1000);
 cout<<"函数f2的定积分值是:"<<jieguo2<<endl;
}

原文地址:https://www.cnblogs.com/javaadu/p/11742822.html