ZigZag Conversion

寻找W型字符的规律：除第一和最后一行外都是对称的。找出循环的长度相应的做出位移即可。比较烦

 1 public class Solution {
 2     public String convert(String s, int nRows) {
 3         // IMPORTANT: Please reset any member data you declared, as
 4         // the same Solution instance will be reused for each test case.
 5         if(nRows == 1)
 6             return s;
 7         char[] mychar = s.toCharArray();
 8         char[] result = new char[mychar.length];
 9         int rows = 2 * nRows - 2;
10         int index = 0;
11         for(int i = 1; i < nRows + 1; i++)
12         {
13             int start = i - 1;
14             boolean odd = true;
15             while(start < result.length){
16                 result[index] = mychar[start];
17                 if(i == 1 || i == nRows)
18                     start += rows;
19                 else if(odd)
20                 {
21                     start += rows - 2 * i + 2;
22                     odd = false;
23                 }
24                 else
25                 {
26                     start += 2 * i - 2;
27                     odd = true;
28                 }
29                 index++;
30             }
31         }
32         return String.valueOf(result);
33         
34     }
35 }