Roman to Integer

Given a roman numeral, convert it to an integer.

Input is guaranteed to be within the range from 1 to 3999.

【罗马数字】

1~9: {"I", "II", "III", "IV", "V", "VI", "VII", "VIII", "IX"};

10~90: {"X", "XX", "XXX", "XL", "L", "LX", "LXX", "LXXX", "XC"};

100~900: {"C", "CC", "CCC", "CD", "D", "DC", "DCC", "DCCC", "CM"};

1000~3000: {"M", "MM", "MMM"}.

//这道题找不到规律,初始做的极为丑陋

C++:

class Solution {
public:
    int romanToInt(string s) {
        
        int i,num=str2num(s[0]),n=s.length(),t1,t2;
        
        for(i=1;i<n;i++)
        {
            t1=str2num(s[i-1]);
            t2=str2num(s[i]);
            if(t1<t2)
            {
                num += t2 - 2*t1;
            }else
            {
                num+=t2;
            }
        }
        
        return num;
    }
    
    int str2num(char& s)
    {
        switch(s)
        {
            case 'I': return 1;  
            case 'V': return 5;  
            case 'X': return 10;  
            case 'L': return 50;  
            case 'C': return 100;  
            case 'D': return 500;  
            case 'M': return 1000; 
        }
    }
};
原文地址:https://www.cnblogs.com/jason1990/p/4641783.html