PKU 1064 Cable master

题目链接:点击打开链接

有n段绳子,给定n段绳子的长度,单位为厘米。求能够把这些绳子分成k段的最长的段的长度。题目中的trick是最小是1cm,长度不能小于1cm,因此要转换成int来解,然后二分可以截得的绳子的长度。

#include <iostream>
#include <string>
#include <algorithm>
using namespace std;
#define INF 100000000
int l[10009];
int n, k;
bool C(int len)
{
	if (len == 0) return false;
	int sum = 0;
	for (int i=0; i<n; i++)
	{
		sum += (int)(l[i] / len);
	}
	if (sum >= k) return true;
	return false;
}

int main()
{
	cout.precision(2);
	while ( cin >> n >> k ) 
	{
		double x;
		for (int i=0; i<n; i++) { cin >> x; l[i] = x * 100; }
		int low = 0, up = INF;
		for (int i=0; i<100; i++)
		{
			int mid = (low + up) / 2;
			if (C(mid)) low = mid;
			else up = mid;
		}
		if (low < 1) puts("0.00");
		else cout << fixed << low * 1.0 / 100 << endl;
	}
	return 0;
}


原文地址:https://www.cnblogs.com/james1207/p/3275651.html