矩阵清零

代码:

  

#include<iostream>
using namespace std ;

int main ()
{
 int row , line  ; //记录矩阵的行数,列数
 while (scanf("%d%d",&row,&line) && (row+line)!=0)
 { 
  int s1=0,s2=0;        //分别记录黑白格子数目
  for(int i=0;i<row;i++)
  {
   for (int j=0;j<line;j++)
   {
    int num;
    cin >> num;
    if((i+j)%2==0)
     s1+=num;
    else
     s2+=num;
   }
  }
  if(s1==s2)
   cout<<"Yes"<<endl;
  else
   cout<<"No"<<endl;
 }
 return 0 ;
}

原文地址:https://www.cnblogs.com/jacklove/p/2943717.html