Game Prediction_贪心

Time Limit: 1000MS		Memory Limit: 10000K
Total Submissions: 10618		Accepted: 5116

Description

Suppose there are M people, including you, playing a special card game. At the beginning, each player receives N cards. The pip of a card is a positive integer which is at most N*M. And there are no two cards with the same pip. During a round, each player chooses one card to compare with others. The player whose card with the biggest pip wins the round, and then the next round begins. After N rounds, when all the cards of each player have been chosen, the player who has won the most rounds is the winner of the game. 



Given your cards received at the beginning, write a program to tell the maximal number of rounds that you may at least win during the whole game. 

Input

The input consists of several test cases. The first line of each case contains two integers m (2�?20) and n (1�?50), representing the number of players and the number of cards each player receives at the beginning of the game, respectively. This followed by a line with n positive integers, representing the pips of cards you received at the beginning. Then a blank line follows to separate the cases. 

The input is terminated by a line with two zeros. 

Output

For each test case, output a line consisting of the test case number followed by the number of rounds you will at least win during the game. 

Sample Input

2 5
1 7 2 10 9

6 11
62 63 54 66 65 61 57 56 50 53 48

0 0

Sample Output

Case 1: 2
Case 2: 4

题意：
　　M个人，每人N张牌，每轮比较谁出的牌大，最大者为胜。现在给定M和N，以及你的牌，要求输出你至少能确保获得几轮的胜利
　　从"至少能赢几轮"可以看出：每个人必定都从最大的牌开始出。(只判定输赢两种情况即可)

#include<iostream>
#include<stdio.h>
#include<algorithm>
using namespace std;
int main()
{
    int n,m,cas=0,a[1005];
    while(cin>>m>>n,m||n)
    {
        cas++;
        for(int i=1;i<=n;i++)
        {
            cin>>a[i];
        }
        sort(a+1,a+n+1);
        int maxn=n*m;
        int n1=0,n2=0;
        for(int i=n;n1+n2!=n;i--)//n1+n2!=n牌未出完
        {
            if(maxn==a[i])
            {
                n1++;
                maxn--;//赢了就减去1；
            }
            else
            {
                n2++;
                maxn-=2;//如果输了，减去2即最大的牌和我手里最大的牌
            }
        }
        printf("Case %d: %d
",cas,n1);
    }
    return 0;
}