【Codeforces】600E. Lomsat gelral

Codeforces 600E. Lomsat gelral

学习了一下dsu on tree

所以为啥是dsu而不是dfs on tree???

这道题先把这棵树轻重链剖分了,然后先处理轻儿子,处理完轻儿子后要把轻儿子的贡献都给删了

然后为了计算这个点的贡献,我把所有轻儿子的贡献加回来

如果这个点是个轻儿子,没什么人权,我就再遍历整棵树把它清空

其实我希望的是把整个数组清空,又不能一个一个清,所以把当前子树遍历一遍清空

唔,感觉说的好短,但是确实是这样的……

#include <bits/stdc++.h>
#define fi first
#define se second
#define pii pair<int,int>
#define mp make_pair
#define pb push_back
#define space putchar(' ')
#define enter putchar('
')
#define eps 1e-10
#define MAXN 100005
#define ba 47
//#define ivorysi
using namespace std;
typedef long long int64;
typedef unsigned int u32;
typedef double db;
template<class T>
void read(T &res) {
    res = 0;T f = 1;char c = getchar();
    while(c < '0' || c > '9') {
	if(c == '-') f = -1;
	c = getchar();
    }
    while(c >= '0' && c <= '9') {
	res = res * 10 +c - '0';
	c = getchar();
    }
    res *= f;
}
template<class T>
void out(T x) {
    if(x < 0) {x = -x;putchar('-');}
    if(x >= 10) {
	out(x / 10);
    }
    putchar('0' + x % 10);
}
struct node {
    int to,next;
}E[MAXN * 2];
int head[MAXN],sumE;
int N,c[MAXN],siz[MAXN],son[MAXN];
int val[MAXN],mval;
int64 sum,ans[MAXN];
bool vis[MAXN];
void add(int u,int v) {
    E[++sumE].to = v;
    E[sumE].next = head[u];
    head[u] = sumE;
}
void dfs(int u,int fa) {
    siz[u] = 1;
    for(int i = head[u] ; i ; i = E[i].next) {
	int v = E[i].to;
	if(v != fa) {
	    dfs(v,u);
	    siz[u] += siz[v];
	    if(siz[v] > siz[son[u]]) son[u] = v;
	}
    }
}
void change(int u,int fa,int k) {
    val[c[u]] += k;
    if(k == -1) vis[u] = 0;
    if(val[c[u]] >= mval) {
	if(val[c[u]] > mval) {mval = val[c[u]];sum = 0;}
	sum += c[u];
    }
    for(int i = head[u] ; i ; i = E[i].next) {
	int v = E[i].to;
	if(v != fa && (!vis[v] || k == -1)) {
	    change(v,u,k);
	}
    }
}
void calc(int u,int fa,bool f) {
    for(int i = head[u] ; i ; i = E[i].next) {
	int v = E[i].to;
	if(v != fa && v != son[u]) {
	    calc(v,u,0);
	}
    }
    if(son[u]) {calc(son[u],u,1);vis[son[u]] = 1;}
    change(u,fa,1);
    ans[u] = sum;
    if(!f) {change(u,fa,-1);sum = 0;mval = 0;}
}
void Solve() {
    read(N);
    for(int i = 1 ; i <= N ; ++i) read(c[i]);
    int a,b;
    for(int i = 1 ; i < N ; ++i) {
	read(a);read(b);
	add(a,b);add(b,a);
    }
    dfs(1,0);
    calc(1,0,1);
    for(int i = 1 ; i <= N ; ++i) {
	out(ans[i]);space;
    }
    enter;
}
int main() {
#ifdef ivorysi
    freopen("f1.in","r",stdin);
#endif
    Solve();
}

原文地址:https://www.cnblogs.com/ivorysi/p/10944016.html