【LOJ】#2534. 「CQOI2018」异或序列

题解

每个数都处理成前缀和，就相当于问([l - 1,r])有几个数对(x,y),(sum[x] ^ sum[y] = k)
直接莫队即可

代码

#include <bits/stdc++.h>
#define fi first
#define se second
#define pii pair<int, int>
#define pdi pair<db, int>
#define mp make_pair
#define pb push_back
#define enter putchar('
')
#define space putchar(' ')
#define eps 1e-8
#define mo 974711
#define MAXN 100005
//#define ivorysi
using namespace std;
typedef long long int64;
typedef double db;
template <class T>
void read(T &res) {
    res = 0;
    char c = getchar();
    T f = 1;
    while (c < '0' || c > '9') {
        if (c == '-') f = -1;
        c = getchar();
    }
    while (c >= '0' && c <= '9') {
        res = res * 10 + c - '0';
        c = getchar();
    }
    res *= f;
}
template <class T>
void out(T x) {
    if (x < 0) {
        x = -x;
        putchar('-');
    }
    if (x >= 10) {
        out(x / 10);
    }
    putchar('0' + x % 10);
}
struct qry_node {
    int l, r, bl, id;
    friend bool operator<(const qry_node &a, const qry_node &b) {
        if (a.bl != b.bl) return a.bl < b.bl;
        if (a.r != b.r) return a.r < b.r;
        if (a.l != b.l) return a.l < b.l;
        return a.id < b.id;
    }
} qry[MAXN];
int64 ans, res[MAXN];
int N, M, K;
int a[MAXN], sum[MAXN], pos[MAXN], tot, p, q, c[MAXN];
void Move(int l, int r) {
    while (q < r) {
        ans += c[K ^ sum[++q]];
        c[sum[q]]++;
    }
    while (p > l) {
        ans += c[K ^ sum[--p]];
        c[sum[p]]++;
    }
    while (q > r) {
        c[sum[q]]--;
        ans -= c[K ^ sum[q--]];
    }
    while (p < l) {
        c[sum[p]]--;
        ans -= c[K ^ sum[p++]];
    }
}
void Solve() {
    read(N);
    read(M);
    read(K);
    for (int i = 1; i <= N; ++i) {
        read(a[i]);
        sum[i] = sum[i - 1] ^ a[i];
    }
    int S = sqrt(N + 1);
    for (int i = 0; i <= N; i += S) {
        int r = min(i + S - 1, N);
        ++tot;
        for (int j = i; j <= r; ++j) pos[j] = tot;
    }
    int l, r;
    for (int i = 1; i <= M; ++i) {
        read(l);
        read(r);
        --l;
        qry[i] = (qry_node){ l, r, pos[l], i };
    }
    p = 0;
    q = 0;
    c[sum[0]] = 1;
    sort(qry + 1, qry + M + 1);
    for (int i = 1; i <= M; ++i) {
        Move(qry[i].l, qry[i].r);
        res[qry[i].id] = ans;
    }
    for (int i = 1; i <= M; ++i) {
        out(res[i]);
        enter;
    }
}
int main() {
    Solve();
    return 0;
}