【Number Steps 专题训练排序】

Number Steps
Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u
Appoint description: 

Description

Starting from point (0,0) on a plane, we have written all non-negative integers 0, 1, 2,... as shown in the figure. For example, 1, 2, and 3 has been written at points (1,1), (2,0), and (3, 1) respectively and this pattern has continued.



You are to write a program that reads the coordinates of a point (x, y), and writes the number (if any) that has been written at that point. (x, y) coordinates in the input are in the range 0...5000.
 

Input

The first line of the input is N, the number of test cases for this problem. In each of the N following lines, there is x, and y representing the coordinates (x, y) of a point.
 

Output

For each point in the input, write the number written at that point or write No Number if there is none.
 

Sample Input

3 4 2 6 6 3 4
 

Sample Output

6 12 No Number
 
 
 1 // Project name : C ( Number Steps ) 
 2 // File name    : main.cpp
 3 // Author       : Izumu
 4 // Date & Time  : Tue Jul 10 21:58:22 2012
 5 
 6 
 7 #include <iostream>
 8 using namespace std;
 9 
10 int main()
11 {
12     int t;
13     cin >> t;
14     
15     while( t-- )
16     {
17         int x, y;
18         cin >> x >> y;
19         
20         if( x==y && x%2==0 )
21         {
22             cout << 2*x << endl;
23         }
24         else if( x==y && x%2==1 )
25         {
26             cout << (2*(x-1))+1 << endl;
27         }
28         else if( x-y==2 && x%2==0 )
29         {
30             cout << (2*(x-2))+2 << endl;
31         }
32         else if( x-y==2 && x%2==1)
33         {
34             cout << (2*(x-3))+3 << endl;
35         }
36         else
37         {
38             cout << "No Number" << endl;
39         }
40         
41     }
42     
43     return 0;
44 }
45 
46 // end 
47 // ism 
原文地址:https://www.cnblogs.com/ismdeep/p/2585359.html