【LeetCode】100

Given two binary trees, write a function to check if they are equal or not.

Two binary trees are considered equal if they are structurally identical and the nodes have the same value.

Solution 1:recursion,the key is to find out all situations of return true and false

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    bool isSameTree(TreeNode* p, TreeNode* q) {
        if(!p && !q)return true;
        if(p && !q)return false;
        if(!p && q)return false;
        if(isSameTree(p->left, q->left) && isSameTree(p->right, q->right) && p->val==q->val)return true;
        return false;
        
    }
};

Solution 2: 非递归,待续

原文地址:https://www.cnblogs.com/irun/p/4719626.html