[面试真题] LeetCode：Remove Element

Given an array and a value, remove all instances of that value in place and return the new length.

The order of elements can be changed. It doesn't matter what you leave beyond the new length.

class Solution {
public:
    int removeElement(int A[], int n, int elem) {
        // Start typing your C/C++ solution below
        // DO NOT write int main() function
        n--;
        for(int i=0; i<=n; i++){
            if(A[i] == elem){
                while(n>i && A[n] == elem){
                    n--;
                }
                A[i] = A[n];
                n--;
            }
        }
        return n+1;
    }
};

Run Status: Accepted!
Program Runtime: 20 milli secs

Progress: 112/112 test cases passed.