LC102 二叉树的层序遍历

思路

使用队列。每次遍历一层节点,在遍历前先获得每层节点的个数,对整层遍历,同时将不为空的左右子节点添加到队列中

代码如下:

class Solution {
public:
    vector<vector<int>> levelOrder(TreeNode* root) {
        vector<vector<int>> res;
        if(root == NULL)
            return res;
        vector<int> level;
        queue<TreeNode*> que;
        que.push(root);
        int levelSize = 0; 
        while(!que.empty()){
            level.clear();
            levelSize = que.size();
            // 遍历完一层
            for(int i = 1; i <= levelSize; i++){
                // 左边
                if(que.front()->left != NULL)
                    que.push(que.front()->left);
                // 右边
                if(que.front()->right != NULL)
                    que.push(que.front()->right);
                level.push_back(que.front()->val);
                que.pop(); 
            }
            res.push_back(level);
        }
        return res;
    }
};
原文地址:https://www.cnblogs.com/imagineincredible/p/13321399.html