HDU 1940

//比赛的时候卡了三个点。今天卡了两个点。真心不愿意再看了。

// 自己按照直线相交的思路的敲得。题意里说了不是按照final rank 给的。但是。这样就和标程输出不同。

//就是觉得AC突然就不那么重要了。也只是揣摩出题人的意思。好无聊。

#include<stdio.h>
#include<iostream>
#include<string.h>
#include<algorithm>
using namespace std;

int maxn = 0x1f1f1f1f;
int minn = 0;

int item[1200];
int fa[1200];
int a[1200];
int b[1200];
int num[1200];
int ac[1200];

int get(char s[])
{
    int num = 0;
    int len = strlen(s);
    for (int i=0; i<len; ++i)
    {
        num = num * 10 + s[i] - '0';
    }
    return num;
}

int main()
{
    int t, p;
    int ci;
    char temp, time[500];
    while(~scanf("%d%d", &t, &p))
    {
        maxn = 0x1f1f1f1f;
        minn = 1;
        if (t == 0 && p == 0)
            break;
        memset(item, 0, sizeof(item));
        memset(a, 0, sizeof(a));
        memset(b, 0, sizeof(b));
        memset(fa, 0, sizeof(fa));
        memset(num, 0, sizeof(num));
        memset(ac, 0, sizeof(ac));

        for (int i=0; i<t; ++i)
        {
            for (int j=0; j<p; ++j)
            {
               scanf("%d", &ci);
               getchar();
               scanf("%s", time);
               if (ci == 0)
                continue;
               if (time[0] == '-')
                   continue;
                else
                {
                    item[i] += 1;
                    int sco = get(time);
                    fa[i] += (sco + (ci - 1) * 20);
                    a[i] += (ci-1);
                    b[i] += sco;
                    num[i] = i+1;
                    if (ci == 1)
                    ac[i] += 1;
                }
            }
        }

        for (int i=0; i<t; ++i)
        {
            if (item[i] == 0) continue;
            if (fa[i] == 0) continue;
            for (int j=0; j<t; ++j)
            {
                if (item[j] == 0) continue;
                if (item[i] != item[j]) continue;
                if (a[i] == a[j]) continue;
                if (fa[j] == 0) continue;
                double t = (b[i] - b[j]) * 1.0 / (a[j] - a[i]);
                int rs, rb;
                if (fa[i] > fa[j])
                {
                    rs = j;
                    rb = i;
                }
                else if (fa[i] < fa[j])
                {
                    rs = i;
                    rb = j;
                }
                else if (fa[i] == fa[j])
                {
                    minn = maxn = 20;
                    continue;
                }
                if (a[rs] > a[rb])
                {
                     if (t<maxn)
                    {
                       if (t == int(t))
                          maxn = t - 1;
                       else maxn = int(t);
                    }
                    if (num[rs] < num[rb] && t == int(t))
                        maxn += 1;
                }
                else if (a[rs] < a[rb])
                {
                    minn = int (t + 1);
                    if (num[rs] < num[rb] && t == int(t))
                        minn -= 1;
                }
            }
        }
        if (minn <= 0)
            minn = 1;
        printf("%d ", minn);
        if (maxn == 0x1f1f1f1f)
        {
            printf("*
");
        }
        else printf("%d
", maxn);
    }
    return 0;
}
LOoK



原文地址:https://www.cnblogs.com/icode-girl/p/4674110.html