luogu P1067 多项式输出模拟

 1 #include <cstdio>
 2 using namespace std;
 3 int n;
 4 int main()
 5 {
 6     scanf("%d",&n);
 7     int tmp;
 8     for (int i = 0;i <= n;i++)
 9     {
10         scanf("%d",&tmp);
11         if (tmp == 0)
12             continue;
13         if (i != 0)
14         {
15             if (tmp > 0)
16                 printf("+");
17             else
18                 printf("-");
19         }else
20         {
21             if (tmp < 0)
22                 printf("-");
23         }
24         if (tmp < 0)
25             tmp *= -1;
26         if (tmp != 1)
27             printf("%d",tmp);
28         if (i == n && tmp == 1)
29             printf("%d",tmp); 
30         if (i <= n - 2)
31             printf("x^%d",n - i);
32         else if (i == n - 1)
33             printf("x");
34     }
35     return 0;
36 }

心之所动且就随缘去吧

luogu P1067 多项式输出 模拟

luogu P1067 多项式输出模拟