*Unique Combination of Factors (因式分解)

A question by dongfeiwww:

打印一个数的所有乘数组合,从大到小,不要有重复

Print all unique combinations of factors of a positive integer. For example given 24:

24*1
12*2
8*3
6*4
6*2*2
4*3*2
3*2*2*2

Solution

Simple DFS.

Code

public List<List<Integer>> factorCombinations(int n) {
    List<List<Integer>> ans = new ArrayList<List<Integer>>();
    helper(ans, n, n / 2, new ArrayList<Integer>());
    return ans;
}

private void helper(List<List<Integer>> ans, int num, int largestFactor,
        List<Integer> path) {
    if (num == 1) {
        ans.add(new ArrayList<Integer>(path));
        return;
    }
    for (int i = largestFactor; i > 1; i--) {
        if (num % i == 0) {
            path.add(i);
            helper(ans, num / i, i, path);
            path.remove(path.size() - 1);
        }
    }
}

 

原文地址:https://www.cnblogs.com/hygeia/p/5151017.html