*Recover rotated sorted array

题目

Given a rotated sorted array, recover it to sorted array in-place.

Example

[4, 5, 1, 2, 3] -> [1, 2, 3, 4, 5]

Challenge

In-place, O(1) extra space and O(n) time.

Clarification

What is rotated array?

  • For example, the orginal array is [1,2,3,4], The rotated array of it can be [1,2,3,4], [2,3,4,1], [3,4,1,2], [4,1,2,3]
 1 /**
 2  * 本代码由九章算法编辑提供。没有版权欢迎转发。
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 6  */
 7 
 8 import java.util.ArrayList;
 9 
10 
11 public class Solution {
12     /**
13      * @param nums: The rotated sorted array
14      * @return: The recovered sorted array
15      */
16     private void reverse(ArrayList<Integer> nums, int start, int end) {
17         for (int i = start, j = end; i < j; i++, j--) {
18             int temp = nums.get(i);
19             nums.set(i, nums.get(j));
20             nums.set(j, temp);
21         }
22     }
23 
24     public void recoverRotatedSortedArray(ArrayList<Integer> nums) {
25         for (int index = 0; index < nums.size() - 1; index++) {
26             if (nums.get(index) > nums.get(index + 1)) {
27                 reverse(nums, 0, index);
28                 reverse(nums, index + 1, nums.size() - 1);
29                 reverse(nums, 0, nums.size() - 1);
30                 return;
31             }
32         }
33     }
34 }
原文地址:https://www.cnblogs.com/hygeia/p/4837033.html