operator.itemgetter() 字典列表排序

## 字典列表排序

 1 students = [
 2     {"name": "Stanley", "age": 22, "score": 92},
 3     {"name": "Peter", "age": 19, "score": 99},
 4     {"name": "Well", "age": 23, "score": 82},
 5     {"name": "Bob", "age": 20, "score": 88},
 6     {"name": "Lily", "age": 22, "score": 95}
 7 ]
 8 students_by_age = sorted(students, key=lambda s: s["age"])
 9 print(students_by_age)
10 """
11 [{'name': 'Peter', 'age': 19, 'score': 99},
12 {'name': 'Bob', 'age': 20, 'score': 88},
13 {'name': 'Stanley', 'age': 22, 'score': 92},
14 {'name': 'Lily', 'age': 22, 'score': 95},
15 {'name': 'Well', 'age': 23, 'score': 82}]
16 """
17 
18 # 使用operator.itemgetter 进行排序，代替sorted函数中的key的匿名函数
19 # 排序速度比匿名函数更快，也支持多个关键字同时排序，同样适用与min(),max()等函数中的key关键字
20 
21 from operator import itemgetter
22 
23 students_by_score_age = sorted(students, key=itemgetter("score", "age"), reverse=True)
24 print(students_by_score_age)
25 """
26 [{'name': 'Peter', 'age': 19, 'score': 99},
27 {'name': 'Lily', 'age': 22, 'score': 95},
28 {'name': 'Stanley', 'age': 22, 'score': 92},
29 {'name': 'Bob', 'age': 20, 'score': 88},
30 {'name': 'Well', 'age': 23, 'score': 82}]
31 """

参考资料：
　　Python Cookbook, 3rd edition, by David Beazley and Brian K. Jones (O’Reilly).