UVA 10041

http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&category=24&problem=982&mosmsg=Submission+received+with+ID+11407931

vito 在一条街选间房子,使得到亲戚家的距离之和最小,求出这个和,即在数组中求出中位数,计算各个数与中位数的差之和

View Code
#include<stdio.h>
#include<math.h>
int main()
{
 int c,a[555],n,i,j,temp,sum,avr;
 scanf("%d",&c);
 while(c--)
    {
     scanf("%d",&n);
     sum=0;
     for(i=0;i<n;i++)
        {
         scanf("%d",&a[i]);
        }
     for(j=1;j<n;j++)
        for(i=0;i<n-j;i++)
           if(a[i]>a[i+1])
              {
               temp=a[i];
               a[i]=a[i+1];
               a[i+1]=temp;
              }
     if(n%2==0)
        avr=a[(n-1)/2];
     else avr=a[n/2];
     for(i=0;i<n;i++)
         sum+=fabs(avr-a[i]);
     printf("%d\n",sum);
    }
 return 0;
}
原文地址:https://www.cnblogs.com/huzhenbo113/p/2951240.html