【Python开发】python重命名文件和遍历文件夹操作

当前文件夹下,把所有文件名中的“50076“替换成”50092“,用Python实现,代码所下:


# encoding: utf-8  
import os  
import os.path  
  
curDir = os.getcwd()  
oldId = "50076"  
newId = "50092"  
for parent, dirnames, filenames in os.walk(curDir):    
    for filename in filenames:  
        if filename.find(oldId)!=-1:  
            newName = filename.replace(oldId, newId)  
            print(filename, "---->", newName)  
            os.rename(os.path.join(parent, filename), os.path.join(parent, newName))  
  
os.system("pause")



附:遍历特定文件夹中的文件以及子文件夹,代码如下:


# encoding: utf-8  
import os  
import os.path  
rootdir = r'D:game'    # 指明被遍历的文件夹  
  
#三个参数:分别返回1.父目录 2.所有文件夹名字(不含路径) 3.所有文件名字  
for parent, dirnames, filenames in os.walk(rootdir):      
    for dirname in dirnames:    #输出文件夹信息  
        print "parent is: " + parent  
        print "dirname is: " + dirname  
  
    for filename in filenames:  #输出文件信息  
        print "parent is: " + parent  
        print "filename is: " + filename  
        print "the full name of the file is: " + os.path.join(parent,filename) #输出文件路径信息  


原文地址:https://www.cnblogs.com/huty/p/8517932.html