php下的jsonp使用实例

参考资料：http://www.cnblogs.com/chopper/archive/2012/03/24/2403945.html 

测试依赖条件： 
项目eetopinOfficial 在hosts绑定 www.eetopin.com域名 
项目sns 在hosts绑定sns.com域名 
测试代码文件及源码： 
eetopinOfficial/testCookie.php 

<?php

header('Content-type: application/json');
//获取回调函数名
$callback = $_GET ['callback'];
$value = $_GET['name'];

//setcookie("name", "", time() - 3600);
setcookie('name', $value, time()+3600*24*30, '/','.eetopin.com', $_SERVER['SERVER_PORT']==443?1:0);

$json = "{"name":"add cookie success $callback $value"}";
echo $callback . "(" . $json . ")";

eetopinOfficial/testJsonp.php 

<?php
header('Content-type: application/json');
//获取回调函数名
$callback = $_REQUEST ['callback'];

if (isset($_COOKIE["name"])){
    $name =  $_COOKIE["name"];
}else{
 $name = "chopper";
}

//json数据
$json = "{"name":"$name","sex":"man"}";

//echo $json;
//echo $callback;

//输出：回调函数名(json数据)
echo $callback . "(" . $json . ")";

//echo $callback ."($json)";

sns/testCookie.php 

<script type="text/javascript" src="http://code.jquery.com/jquery-latest.js"></script>
<script type="text/javascript">
    $.getJSON("http://www.eetopin.com/testCookie.php?name=lunzi30108&callback=?",function(data){
        alert(data.name);
    });
</script>

sns/testJsonp.php 

<script type="text/javascript" src="http://code.jquery.com/jquery-latest.js"></script>
<script type="text/javascript">
    $.getJSON("http://www.eetopin.com/testJsonp.php?callback=?",function(data){
        alert(data.name + " is a a" + data.sex);
    });
</script>

测试步骤： 
1、http://sns.com/testCookie.php 
2、http://sns.com/testJsonp.php