全组合

输入n个数,求这n个数构成的集合的所有自己

3

1 2 3

输出

1

1 2

1 2 3

1 3

2

2 3

3

#include<cstdio>
#include<cstring>
using namespace std;
const int maxn = 100;

int n,m;
int rcd[maxn],num[maxn],vis[maxn];

int read_input(){

   if(scanf("%d",&n)==EOF)
        return 0;
    for(int i=0;i<n;i++)
        scanf("%d",&num[i]);
    return 1;
}

void full_combination(int l,int p){

        for(int i=0;i<l;i++){
            printf("%d",rcd[i]);
        if(i<m-1)
            printf(" ");
        }
        printf("
");


    for(int i=p;i<n;i++){
        rcd[l]=num[i];
        full_combination(l+1,i+1);

    }
}
int main() {
    while(read_input()){

        full_combination(0,0);

    }

    return 0;
}

  用向量表示

#include<cstdio>
#include<string.h>
using namespace std;
const int MAXN = 1000;
int vis[MAXN],num[MAXN],rcd[MAXN];
int n;
int input(){
    if(scanf("%d",&n)!=1)
        return 0;
    for(int i=0;i<n;i++)
        scanf("%d",&num[i]);
    memset(vis,0,sizeof(vis));
    return 1;
}
void print_subset(int p){
        if(p==n){
            for(int i=0;i<p;i++)
            if(vis[i])
                printf("%d ",num[i]);
        printf("
");
        return ;
        }

        vis[p]=1;
        print_subset(p+1);
        vis[p]=0;
        print_subset(p+1);


}
int main(){
    while(input())
        print_subset(0);
    return 0;
}

  用位运算表示

#include<cstdio>
#include<string.h>
using namespace std;
const int maxn =100 ;
int num[maxn];

void print_subset(int n,int s){
    for(int i=0;i<n;i++)
        if(s&(1<<i))
            printf("%d ",num[i]);
    printf("
");
}
int main(){
    int n;
    while(scanf("%d",&n)==1)
    {
        for(int i=0;i<n;i++)
            scanf("%d",&num[i]);
        for(int i=0;i<(1<<n);i++)
        print_subset(n,i);
    }
    return 0;
}

  

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原文地址:https://www.cnblogs.com/huicpc0212/p/4185980.html