mysql 笔记2

-- 数据的准备
    -- 创建一个数据库
    CREATE DATABASE python_test CHARSET=utf8;

    -- 使用一个数据库
    USE python_test;

    -- 显示使用的当前数据是哪个?
    SELECT DATABASE();

    -- 创建一个数据表
    -- students表
    CREATE TABLE students(
        id INT UNSIGNED PRIMARY KEY AUTO_INCREMENT NOT NULL,
        NAME VARCHAR(20) DEFAULT '',
        age TINYINT UNSIGNED DEFAULT 0,
        height DECIMAL(5,2),
        gender ENUM('','','中性','保密') DEFAULT '保密',
        cls_id INT UNSIGNED DEFAULT 0,
        is_delete BIT DEFAULT 0
    );

    -- classes表
    CREATE TABLE classes (
        id INT UNSIGNED AUTO_INCREMENT PRIMARY KEY NOT NULL,
        NAME VARCHAR(30) NOT NULL
    );



-- 查询
    -- 查询所有字段
    -- select * from 表名;
    SELECT * FROM students;
    SELECT * FROM classes;
    SELECT id, NAME FROM classes;

    -- 查询指定字段
    -- select 列1,列2,... from 表名;
    SELECT NAME, age FROM students;
    
    -- 使用 as 给字段起别名
    -- select 字段 as 名字.... from 表名;
    SELECT NAME AS 姓名, age AS 年龄 FROM students;

    -- select 表名.字段 .... from 表名;
    SELECT students.name, students.age FROM students;

    
    -- 可以通过 as 给表起别名
    -- select 别名.字段 .... from 表名 as 别名;
    SELECT students.name, students.age FROM students;
    SELECT s.name, s.age FROM students AS s;
    -- 失败的select students.name, students.age from students as s;


    -- 消除重复行
    -- distinct 字段
    SELECT DISTINCT gender FROM students;


-- 条件查询
    -- 比较运算符
        -- select .... from 表名 where .....
        -- >
        -- 查询大于18岁的信息
        SELECT * FROM students WHERE age>18;
        SELECT id,NAME,gender FROM students WHERE age>18;

        -- <
        -- 查询小于18岁的信息
        SELECT * FROM students WHERE age<18;

        -- >=
        -- <=
        -- 查询小于或者等于18岁的信息

        -- =
        -- 查询年龄为18岁的所有学生的名字
        SELECT * FROM students WHERE age=18;


        -- != 或者 <>


    -- 逻辑运算符
        -- and
        -- 18到28之间的所以学生信息
        SELECT * FROM students WHERE age>18 AND age<28;
        -- 失败select * from students where age>18 and <28;


        -- 18岁以上的女性
        SELECT * FROM students WHERE age>18 AND gender="女";
        SELECT * FROM students WHERE age>18 AND gender=2;


        -- or
        -- 18以上或者身高查过180(包含)以上
        SELECT * FROM students WHERE age>18 OR height>=180;


        -- not
        -- 不在 18岁以上的女性 这个范围内的信息
        -- select * from students where not age>18 and gender=2;
        SELECT * FROM students WHERE NOT (age>18 AND gender=2);

        -- 年龄不是小于或者等于18 并且是女性
        SELECT * FROM students WHERE (NOT age<=18) AND gender=2;


    -- 模糊查询
        -- like 
        -- % 替换1个或者多个
        -- _ 替换1个
        -- 查询姓名中 以 "小" 开始的名字
        SELECT NAME FROM students WHERE NAME="小";
        SELECT NAME FROM students WHERE NAME LIKE "小%";

        -- 查询姓名中 有 "小" 所有的名字
        SELECT NAME FROM students WHERE NAME LIKE "%%";

        -- 查询有2个字的名字
        SELECT NAME FROM students WHERE NAME LIKE "__";

        -- 查询有3个字的名字
        SELECT NAME FROM students WHERE NAME LIKE "__";

        -- 查询至少有2个字的名字
        SELECT NAME FROM students WHERE NAME LIKE "__%";


        -- rlike 正则
        -- 查询以 周开始的姓名
        SELECT NAME FROM students WHERE NAME RLIKE "^周.*";

        -- 查询以 周开始、伦结尾的姓名
        SELECT NAME FROM students WHERE NAME RLIKE "^周.*伦$";


    -- 范围查询
        -- in (1, 3, 8)表示在一个非连续的范围内
        -- 查询 年龄为18、34的姓名
        SELECT NAME,age FROM students WHERE age=18 OR age=34;
        SELECT NAME,age FROM students WHERE age=18 OR age=34 OR age=12;
        SELECT NAME,age FROM students WHERE age IN (12, 18, 34);


        
        -- not in 不非连续的范围之内
        -- 年龄不是 18、34岁之间的信息
        SELECT NAME,age FROM students WHERE age NOT IN (12, 18, 34);


        -- between ... and ...表示在一个连续的范围内
        -- 查询 年龄在18到34之间的的信息
        SELECT NAME, age FROM students WHERE age BETWEEN 18 AND 34;

        
        -- not between ... and ...表示不在一个连续的范围内
        -- 查询 年龄不在在18到34之间的的信息
        SELECT * FROM students WHERE age NOT BETWEEN 18 AND 34;
        SELECT * FROM students WHERE NOT age BETWEEN 18 AND 34;
        -- 失败的select * from students where age not (between 18 and 34);


    -- 空判断
        -- 判空is null
        -- 查询身高为空的信息
        SELECT * FROM students WHERE height IS NULL;
        SELECT * FROM students WHERE height IS NULL;
        SELECT * FROM students WHERE height IS NULL;

        -- 判非空is not null
        SELECT * FROM students WHERE height IS NOT NULL;



-- 排序
    -- order by 字段
    -- asc从小到大排列,即升序
    -- desc从大到小排序,即降序

    -- 查询年龄在18到34岁之间的男性,按照年龄从小到到排序
    SELECT * FROM students WHERE (age BETWEEN 18 AND 34) AND gender=1;
    SELECT * FROM students WHERE (age BETWEEN 18 AND 34) AND gender=1 ORDER BY age;
    SELECT * FROM students WHERE (age BETWEEN 18 AND 34) AND gender=1 ORDER BY age ASC;


    -- 查询年龄在18到34岁之间的女性,身高从高到矮排序
    SELECT * FROM students WHERE (age BETWEEN 18 AND 34) AND gender=2 ORDER BY height DESC;
    

    -- order by 多个字段
    -- 查询年龄在18到34岁之间的女性,身高从高到矮排序, 如果身高相同的情况下按照年龄从小到大排序
    SELECT * FROM students WHERE (age BETWEEN 18 AND 34) AND gender=2 ORDER BY height DESC,id DESC;


    -- 查询年龄在18到34岁之间的女性,身高从高到矮排序, 如果身高相同的情况下按照年龄从小到大排序,
    -- 如果年龄也相同那么按照id从大到小排序
    SELECT * FROM students WHERE (age BETWEEN 18 AND 34) AND gender=2 ORDER BY height DESC,age ASC,id DESC;

    
    -- 按照年龄从小到大、身高从高到矮的排序
    SELECT * FROM students ORDER BY age ASC, height DESC;


-- 聚合函数
    -- 总数
    -- count
    -- 查询男性有多少人,女性有多少人
    SELECT * FROM students WHERE gender=1;
    SELECT COUNT(*) FROM students WHERE gender=1;
    SELECT COUNT(*) AS 男性人数 FROM students WHERE gender=1;
    SELECT COUNT(*) AS 女性人数 FROM students WHERE gender=2;


    -- 最大值
    -- max
    -- 查询最大的年龄
    SELECT age FROM students;
    SELECT MAX(age) FROM students;

    -- 查询女性的最高 身高
    SELECT MAX(height) FROM students WHERE gender=2;

    -- 最小值
    -- min

    
    -- 求和
    -- sum
    -- 计算所有人的年龄总和
    SELECT SUM(age) FROM students;

    
    -- 平均值
    -- avg
    -- 计算平均年龄
    SELECT AVG(age) FROM students;


    -- 计算平均年龄 sum(age)/count(*)
    SELECT SUM(age)/COUNT(*) FROM students;


    -- 四舍五入 round(123.23 , 1) 保留1位小数
    -- 计算所有人的平均年龄,保留2位小数
    SELECT ROUND(SUM(age)/COUNT(*), 2) FROM students;
    SELECT ROUND(SUM(age)/COUNT(*), 3) FROM students;

    -- 计算男性的平均身高 保留2位小数
    SELECT ROUND(AVG(height), 2) FROM students WHERE gender=1;
    -- select name, round(avg(height), 2) from students where gender=1;

-- 分组

    -- group by
    -- 按照性别分组,查询所有的性别
    SELECT NAME FROM students GROUP BY gender;
    SELECT * FROM students GROUP BY gender;
    SELECT gender FROM students GROUP BY gender;
    -- 失败select * from students group by gender;

    -- 计算每种性别中的人数
    SELECT gender,COUNT(*) FROM students GROUP BY gender;


    -- 计算男性的人数
    SELECT gender,COUNT(*) FROM students WHERE gender=1 GROUP BY gender;


    -- group_concat(...)
    -- 查询同种性别中的姓名
     SELECT gender,GROUP_CONCAT(NAME) FROM students WHERE gender=1 GROUP BY gender;
     SELECT gender,GROUP_CONCAT(NAME, age, id) FROM students WHERE gender=1 GROUP BY gender;
     SELECT gender,GROUP_CONCAT(NAME, "_", age, " ", id) FROM students WHERE gender=1 GROUP BY gender;

    -- having
    -- 查询平均年龄超过30岁的性别,以及姓名 having avg(age) > 30
    SELECT gender, GROUP_CONCAT(NAME),AVG(age) FROM students GROUP BY gender HAVING AVG(age)>30;
    
    -- 查询每种性别中的人数多于2个的信息
    SELECT gender, GROUP_CONCAT(NAME) FROM students GROUP BY gender HAVING COUNT(*)>2;



-- 分页
    -- limit start, count

    -- 限制查询出来的数据个数
    SELECT * FROM students WHERE gender=1 LIMIT 2;

    -- 查询前5个数据
    SELECT * FROM students LIMIT 0, 5;

    -- 查询id6-10(包含)的书序
    SELECT * FROM students LIMIT 5, 5;


    -- 每页显示2个,第1个页面
    SELECT * FROM students LIMIT 0,2;

    -- 每页显示2个,第2个页面
    SELECT * FROM students LIMIT 2,2;

    -- 每页显示2个,第3个页面
    SELECT * FROM students LIMIT 4,2;

    -- 每页显示2个,第4个页面
    SELECT * FROM students LIMIT 6,2; -- -----> limit (第N页-1)*每个的个数, 每页的个数;

    -- 每页显示2个,显示第6页的信息, 按照年龄从小到大排序
    -- 失败select * from students limit 2*(6-1),2;
    -- 失败select * from students limit 10,2 order by age asc;
    SELECT * FROM students ORDER BY age ASC LIMIT 10,2;

    SELECT * FROM students WHERE gender=2 ORDER BY height DESC LIMIT 0,2;



-- 连接查询
    -- inner join ... on

    -- select ... from 表A inner join 表B;
    SELECT * FROM students INNER JOIN classes;

    -- 查询 有能够对应班级的学生以及班级信息
    SELECT * FROM students INNER JOIN classes ON students.cls_id=classes.id;

    -- 按照要求显示姓名、班级
    SELECT students.*, classes.name FROM students INNER JOIN classes ON students.cls_id=classes.id;
    SELECT students.name, classes.name FROM students INNER JOIN classes ON students.cls_id=classes.id;

    -- 给数据表起名字
    SELECT s.name, c.name FROM students AS s INNER JOIN classes AS c ON s.cls_id=c.id;

    -- 查询 有能够对应班级的学生以及班级信息,显示学生的所有信息,只显示班级名称
    SELECT s.*, c.name FROM students AS s INNER JOIN classes AS c ON s.cls_id=c.id;
    
    -- 在以上的查询中,将班级姓名显示在第1列
    SELECT c.name, s.* FROM students AS s INNER JOIN classes AS c ON s.cls_id=c.id;

    -- 查询 有能够对应班级的学生以及班级信息, 按照班级进行排序
    -- select c.xxx s.xxx from student as s inner join clssses as c on .... order by ....;
    SELECT c.name, s.* FROM students AS s INNER JOIN classes AS c ON s.cls_id=c.id ORDER BY c.name;

    -- 当时同一个班级的时候,按照学生的id进行从小到大排序
    SELECT c.name, s.* FROM students AS s INNER JOIN classes AS c ON s.cls_id=c.id ORDER BY c.name,s.id;

    -- left join
    -- 查询每位学生对应的班级信息
    SELECT * FROM students AS s LEFT JOIN classes AS c ON s.cls_id=c.id;

    -- 查询没有对应班级信息的学生
    -- select ... from xxx as s left join xxx as c on..... where .....
    -- select ... from xxx as s left join xxx as c on..... having .....
    SELECT * FROM students AS s LEFT JOIN classes AS c ON s.cls_id=c.id HAVING c.id IS NULL;
    SELECT * FROM students AS s LEFT JOIN classes AS c ON s.cls_id=c.id WHERE c.id IS NULL;

    -- right join   on
    -- 将数据表名字互换位置,用left join完成

-- 自关联
    -- 省级联动 url:http://demo.lanrenzhijia.com/2014/city0605/

    -- 查询所有省份
    SELECT * FROM areas WHERE pid IS NULL;

    -- 查询出山东省有哪些市
    SELECT * FROM areas AS province INNER JOIN areas AS city ON city.pid=province.aid HAVING province.atitle="山东省";
    SELECT province.atitle, city.atitle FROM areas AS province INNER JOIN areas AS city ON city.pid=province.aid HAVING province.atitle="山东省";

    -- 查询出青岛市有哪些县城
    SELECT province.atitle, city.atitle FROM areas AS province INNER JOIN areas AS city ON city.pid=province.aid HAVING province.atitle="青岛市";
    SELECT * FROM areas WHERE pid=(SELECT aid FROM areas WHERE atitle="青岛市")


-- 子查询
    -- 标量子查询
    -- 查询出高于平均身高的信息

    -- 查询最高的男生信息
    SELECT * FROM students WHERE height = 188;
    SELECT * FROM students WHERE height = (SELECT MAX(height) FROM students);

    -- 列级子查询
    -- 查询学生的班级号能够对应的学生信息
    -- select * from students where cls_id in (select id from classes);
原文地址:https://www.cnblogs.com/huazhou695/p/9899488.html