汉明距离

The Hamming distance between two integers is the number of positions at which the corresponding bits are different.

Given two integers x and y, calculate the Hamming distance.

Note:

0 ≤ xy < 231.

Example:

Input: x = 1, y = 4

Output: 2

Explanation:
1   (0 0 0 1)
4   (0 1 0 0)
       ↑   ↑

The above arrows point to positions where the corresponding bits are different.

Solution:
int hammingDistance(int x, int y) {
        int n,sum;
        n=x^y;
        while(n)
        {
            ++sum;
            n&=n-1;
        }
        return sum;
    }

  



原文地址:https://www.cnblogs.com/huangzhenxiong/p/7609842.html