递归

def f4(a1,a2):

  print(a1,a2)

  if a1>1000:

    return

  #a1=0;a2=1;a3=1

  #a1=1;a2=1;a3=2

  a3 = a1 + a2

  f4(a2,a3)

f4(0,1)

斐波那契数列第十个数

def f5(depth,a1,a2):

  print(depth)

  if depth == 10:

    return a1

  a3=a1+a2

  

  r = f5(depth+1,a2,a3)

  return r

ret =f5(1,0,1)

原文地址:https://www.cnblogs.com/huangguabushihaogua/p/9239190.html