1.8字符串及分析 翻转子串

//无论分割点在何处，s2总是s1S1的子串
class ReverseEqual {
public:
    bool checkReverseEqual(string s1, string s2) {
        // write code here
        int len1 = s1.length();
        int len2 = s2.length();
        if (len1 == len2 && len1 > 0)
        {
            string s1s1 = s1 + s1;
            for(int i=0;i<len1;i++)
            {
                if (s1s1.substr(i, len2) == s2)
                    return true;
            }
        }
        return false;
    }
};