测试for循环计算耗时

import time
start = time.time()
for i in range(1000):
    result = []
    for m in range(10000):
        result.append(i*1000+m*100)
end=time.time()
print("耗时:{0}".format(end-start))


start2 = time.time()
for i in range(1000):
    result = []
    c=i*1000
    for m in range(10000):
        result.append(c+m*100)
end2=time.time()
print("耗时:{0}".format(end2-start2))
原文地址:https://www.cnblogs.com/hsinfo/p/13663658.html