c++笔试题两道，求解当中一道

1.Implement a functionthat prints the numbers from 1 to 100.But for multiples of three(3) print “Zif”insteadof the number and for the multiples of five(5) print “Nab”. For numbers whichare multiples of both three and five print “ZifNab”.

void printZifNab(int from, int to)
	{
		if (from > to) return;
		for (int i = from; i <= to; i++)
		{
			if ((i % 3 == 0) && (i % 5 == 0))
			{
				printf("ZifNab
");
			}
			else if ((i % 3 == 0))
			{
				printf("Zif
");
			}  
			else if ((i % 5 == 0))
			{
				printf("Nab
");
			}
			else {
				printf("%d
", i);
			}
		}
	}

2. unsigned short ConvertRGB888toRBG565(unsigned int nSourceColor)

Parameters: nSourceColor – 32 Bits RGB color to convert.

Return: The converted color as a 16 Bits RGB color.

This function converts an RGB 32 bits color format to RGB 16 bits color format. The 32 bits formats contains 8 bits of empty padding.8 bits for RED.8 bits for GREEN and 8 bits for BLUE. In that order. Now you have to down convert this value to 16 bits. By have 5 bits for RED, 6 bits for GREEN and finally 5 bits for the BLUE.

Color Help:

Red = 0x00FF0000

Green = 0x0000FF00;

Blue = 0x000000FF;

White = 0x00FFFFFF;

Black = 0x00000000;

第二题求解。