最近工作中遇到一个问题：要在一大堆 中文字符串中 分割 : 中文冒号：由于中文是unicode 所以用不了 strtok 函数。自己分割的第一步就是要自己找到固定中文字符的位置：
#include <stdio.h>
#include <string.h>
#include <stdio.h>
#include <stdlib.h>
#include <locale.h>
#include <wchar.h>
int chinese_or_english(char *str,int len)
{
// char *p=NULL;
char chinese[4] = {0};
for (int i = 0; i < len; i++) {
if ((str[i] & 0x80) == 0) { //chinese:the top is 1
// printf("alpha:%c
", str[i]);
}
else {
chinese[0] = str[i];
chinese[1] = str[i + 1];
chinese[2] = str[i + 2];
i++;
i++;
printf("chinese:%s i is %d
", chinese,i);
if(strcmp(chinese,"：")==0 )
{
//p=str+i;
printf("find >>>>>>>>>>>>>> chinese:%s i is %d
", chinese,i);
return i;
}
}
}
}
int main()
{
char buff_s[128]="我算出来了，等于：二";
printf("buff_s len is [%d]
",strlen(buff_s));
//char p=buff_s;
int i =0;
char want_buffer[64]={" "};
int n=0;
char *r=NULL;
n=chinese_or_english(buff_s,strlen(buff_s));
int j=0;
printf("n is %d
",n);
if(n !=0)
{
//r=chinese_or_english+n;
for(i=n+1;i<strlen(buff_s);i++)
{
want_buffer[j]=buff_s[i];
j++;
printf("i is %d
",i);
}
}
//want_buffer[i]=' ';
printf("want_buffer is %s
",want_buffer);
/*
for(i=0;i<30;i++)
{
if(i%3==0 && i >0)
{
printf("%c%c%c
",buff_s[i-1],buff_s[i],buff_s[i+1]);
printf("
");
}
printf("%x ",buff_s[i]);
}
*/
/*
while(p != "：")
{
printf("*p is %c
",*p);
p++;
}
printf("p====：,ps is %c%c
",*p,*(p+1));
char*temp = strtok(buff_s,"：");
while(temp)
{
printf("%s
",temp);
temp = strtok(NULL,"：");
}
*/
return 0;
}