javascript 截取url参数

1         var url="http://127.0.0.1:8080/photo/list.jsp?page=2&user=hongchen";
2         var params_arr = url.substr(url.indexOf('?')+1).split("&");
3         var params = new Array();
4         for (var i = params_arr.length - 1; i >= 0; i--) {
5             params[params_arr[i].split("=")[0]] = params_arr[i].split("=")[1];
6         };
7         alert(params["page"]);
原文地址:https://www.cnblogs.com/hongchenok/p/3596114.html