HDU 2120 Ice_cream's world I

 

              Ice_cream's world I



 

Problem Description
ice_cream's world is a rich country, it has many fertile lands. Today, the queen of ice_cream wants award land to diligent ACMers. So there are some watchtowers are set up, and wall between watchtowers be build, in order to partition the ice_cream’s world. But how many ACMers at most can be awarded by the queen is a big problem. One wall-surrounded land must be given to only one ACMer and no walls are crossed, if you can help the queen solve this problem, you will be get a land.
 

 

Input
In the case, first two integers N, M (N<=1000, M<=10000) is represent the number of watchtower and the number of wall. The watchtower numbered from 0 to N-1. Next following M lines, every line contain two integers A, B mean between A and B has a wall(A and B are distinct). Terminate by end of file.
 

 

Output
Output the maximum number of ACMers who will be awarded.
One answer one line.
 

 

Sample Input
8 10
0 1
1 2
1 3
2 4
3 4
0 5
5 6
6 7
3 6
4 7
 

 

Sample Output
3
 
 1 #include<cstdio>
 2 using namespace std;
 3 
 4 int bin[1005];
 5 int count;
 6 
 7 int find(int x)
 8 {
 9     int r=x;
10     while(bin[r]!=r)
11     r=bin[r];
12     int temp=x;
13     while(temp!=r)
14     {
15         int j=bin[temp];
16         bin[temp]=r;
17         temp=j;
18     }
19     return r;
20 }
21 
22 void merge(int x,int y)
23 {
24     int fx=find(x);
25     int fy=find(y);
26     if(fx!=fy)
27     bin[fy]=fx;
28     else
29     count++;
30 }
31 
32 int main()
33 {
34     //freopen("in.txt","r",stdin);
35     int m,n,a,b;
36     while(scanf("%d%d",&m,&n)!=EOF)
37     {
38         count=0;
39         for(int i=0;i<m;i++)
40         bin[i]=i;
41         for(int i=0;i<n;i++)
42         {
43             scanf("%d%d",&a,&b);
44             merge(a,b);
45         }
46         printf("%d
",count);
47     }
48     return 0;
49 }
原文地址:https://www.cnblogs.com/homura/p/4686931.html