数组对象去重

方法一 
let t=[{id:1111,name:'nnnn'},{id:1111,name:'nnnn'},{id:1111,name:'nnnn'},{id:2222,name:'mmmm'}];
                let list = [];
                let idList = [];
                t.forEach((item)=>{
                    if(!idList.includes(item.id)){
                        idList.push(item.id);
                        idList = Array.from(new Set([...idList]));
                        list.push(item)
                    }
                });

思路：把数组对象去重用数组去重作为判断

方法二

let obj = {};
t = t.reduce((item, next) =>{
    if(!obj[next.id]){
        obj[next.id] = item.push(next)
    }
    return item;
}, []);

方法二理解起来有点难度哦

方法三

let obj = {};
t.forEach((item)=>{
    if(!obj[item.id]){
        obj[item.id] = item.id;
        list.push(item)
    }
});