内置函数


# l = [4,1,5,2,7]
# l1 = reversed(l)
# print(l1)          # 保留原列表并返回一个反向的迭代器

# slice类似切片
# t = (123,32,1,34,56,122 )
# sli = slice(1,5,2)
# print(t[sli])
# print(t[1:5:2])

# print(format('aaa', '<33'))
# print(format('aaa', '>33'))
# print(format('aaa', '^33'))

# 转换为bytes类型
# print(bytes('你好',encoding='UTF-8'))   # unicode转换成utf-8的bytes
# print(bytearray('你好',encoding='UTF-8'))   # 转换为bytearray类型,可修改里面

# 查unicode
# print(ord('1'))
# print(ord('好'))
# print(chr(88))

# 查ascii
# print(ascii('好'))
# print(1)

# print(all(['qwe','',True]))            # all只要为空,就返回false
# print(all(['qwe']))
# print(any(['qwe','',True]))            # any有一个为空就返回true

# 拉链,根据最短的那个输出元祖
# l = [1,2,3,4]
# t = ('a','b',(1,2))
# d = {'name':'chen',1:1}
# for i in zip(l,t,d):
#     print(i)                  #  (1, 'a', 'name'),(2, 'b', 1)


# def is_old(n):
#     return n % 2 == 1
#
# filter(function or None, iterable)  filter过滤,类似列表推导,只不过传入的是函数名和可迭代的
# 该函数根据function参数返回的结果是否为真来过滤list参数中的项,filter只管筛选,不会改变原来的值
# f = filter(is_old, [1,2,4,56,7,8,89])
# print(f)
# for i in f:
#     print(i)


# map两个参数一个是函数名,另一个是列表或元组,执行前后元素个数不变,值可能发生改变
# m = map(abs, [1,-4,6,-8])
# print(m)
# for i in m:
#     print(i)

# def map_cheng(x):
#     return x * x
#
# m = map(map_cheng, [1,2,3,4])
# for i in m:
#     print(i)

# sorted生成新的列表而不改变原列表,占内存    l.sort()会改变
# l = [-2,5,4,1,-78]
# sort_l = sorted(l)
# print(sort_l)
# sort_l2 = sorted(l, key=abs,reverse=True)
# print(sort_l2)


# print(locals())
# print(globals())

# 迭代器 __next__()
# next()
# iter()

# range(10)
# print('__next__' in dir(range(1,11,2)))

# dir 查看一个变量拥有的方法
# print(dir([]))

# 查看帮助文档
# help(str)

# f = open('w.py')
# print(f.writable())

# id()
# hash 对于相同可hash数据的hash值在一次程序的执行过程中总是不变的(不可变数据类型)
# print(hash(12345))
# print(hash('sdfsdf'))

# ret = input('input: ')

# print('aaaaaaa',end='')  #指定输出的结束符,默认end='
'回车
# print('aaaaaaa',sep='')  #指定输出多个值之间的分隔符,这里输出一排a
# print('aaaaaaa',file=f)  #写入到f.write()

# exec('print(123)')     # 执行print,没有返回值
# eval('print(123)')     # 有返回值

# print(bin(3))           # 二进制
# print(oct(10))          # 八进制
# print(hex(10))          # 十六进制

# print(abs(-34))           # 绝对值
# print(divmod(7,2))          # 求结果和求余,返回元祖(3,1)
# print(round(3.1333, 3))     # 3.133
# print(pow(2,3))
# print(pow(2,3,3))           #pow幂运算,再对3求余

# print(sum([1,2,3,4]))
# print(min([1,2,3,4]))
# print(min((1,2,3,-4),key=abs))
# print(max([1,2,3,4]))
# print(max((1,2,3,-4),key=abs))
原文地址:https://www.cnblogs.com/hhsh/p/9563354.html