js获取页面传来参数的方法

function GetQueryString(name) { 
   var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)","i");
var r = window.location.search.substr(1).match(reg);
   if (r!=null) return (r[2]);
   return null;
}

var sname = GetQueryString("name");
if(sname!=null) {
  var sname_ = decodeURIComponent(sname);
  alert(sname_);
}

测试:abcd.html?name=xyz

弹出xyz

原文地址:https://www.cnblogs.com/henuyuxiang/p/6567856.html