杭电 oj2602~（0-1背包问题）

Bone Collector

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 51417    Accepted Submission(s): 21634

Problem Description

Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?

 

Input

The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.

 

Output

One integer per line representing the maximum of the total value (this number will be less than 2³¹).

 

Sample Input

1 5 10 1 2 3 4 5 5 4 3 2 1

 

Sample Output

14

 

Author

Teddy

 

Source

HDU 1st “Vegetable-Birds Cup” Programming Open Contest

 

简单的0-1背包问题 ~

 

#include<iostream>
using namespace std;
int main()
{
    int t;
    int w[1050];
    int v[1050];
    int d[1050][1050];
    while(cin>>t)
    {
        while(t--)
        {
            int n,c;
            cin>>n>>c;

            for(int i=1;i<=n;i++)
                cin>>w[i];
            for(int i=1;i<=n;i++)
                cin>>v[i];
            for(int i=1;i<=n;i++)
                for(int j=0;j<=c;j++)
            {
                d[i][j]=(i==1?0:d[i-1][j]);
                if(j>=v[i]) d[i][j]=max(d[i][j],d[i-1][j-v[i]]+w[i]);
            }

            cout<<d[n][c]<<endl;

        }

    }
    return 0;
}