根据我开发的邮件接口上调用操作，触发告警
GO的WEB编程（GIN实现邮件接口报警）
Gin编写邮件接口（支持多人发送）
Gin编写邮件告警接口（添加优化日志记录）
首先，我们Linux操作系统可以创建多个用户账号。
但是为了系统安全考虑，我们会给账号密码设置有效期和复杂难度，防止非法操作爆破我们的机器。
但是每次修改完，到规定时间需要修改账号密码，这个每次人工来看，比较麻烦，所以做个账号密码到期的警告。当密码快要过期时，我们可以发邮件告警。
账号密码过期设置
function Check_Password_Policy(){
#查看系统账户策略:密码失效时间90天、密码到期提醒时间14天
echo "========正在检查账户密码失效时间========"
Check_Pass_Poli=`grep -E "^PASS_MAX_DAYS|^PASS_WARN_AGE" /etc/login.defs | wc -l`
cp /etc/login.defs{,_bak$Date_Time}
if [ $Check_Pass_Poli -lt 2 ];then
echo -e "\033[31;40m当前系统未对账户密码进行失效时间设置、密码到期提醒设置\033[0m"
sed -i '$iPASS_MAX_DAYS 90' /etc/login.defs && echo -e "\033[32;40m 修改成功 \033[0m" || echo -e "\033[31;40m 修改失败 \033[0m"
sed -i '$iPASS_WARN_AGE 14' /etc/login.defs && echo -e "\033[32;40m 修改成功 \033[0m" || echo -e "\033[31;40m 修改失败 \033[0m"
else
PAMAX=`grep -E "^PASS_MAX_DAYS" /etc/login.defs | awk -F" " '{ print $2 }'`
PAWARN=`grep -E "^PASS_WARN_AGE" /etc/login.defs | awk -F" " '{ print $2 }'`
if [ $PAMAX -le 90 ];then
echo -e "\033[32;40m密码失效时间为$PAMAX天，符合标准\033[0m";
else
echo -e "\033[31;40m密码失效时间为$PAMAX天，不符合标准\033[0m";
sed -i 's/^PASS_MAX_DAYS.*/PASS_MAX_DAYS 90/' /etc/login.defs && echo -e "\033[32;40m 修改成功 \033[0m" || echo -e "\033[31;40m 修改失败 \033[0m"
fi
if [ $PAWARN -ge 14 ];then
echo -e "\033[32;40m密码到期提醒时间为$PAWARN天，符合标准\033[0m";
else
echo -e "\033[31;40m密码到期提醒时间为$PAWARN天，不符合标准\033[0m";
sed -i 's/^PASS_WARN_AGE.*/PASS_WARN_AGE 14/' /etc/login.defs && echo -e "\033[32;40m 修改成功 \033[0m" || echo -e "\033[31;40m 修改失败 \033[0m"
fi
fi
#chage --warndays 14 root && echo -e "\033[32;40m 修改成功 \033[0m" || echo -e "\033[31;40m 修改失败 \033[0m"
#chage --maxdays 90 root && echo -e "\033[32;40m 修改成功 \033[0m" || echo -e "\033[31;40m 修改失败 \033[0m"
}密码复杂度设置
function Check_User_Policy(){
#查看系统账户策略:密码最小长度12位、密码复杂度为大小写英文字母、数字、特殊字符
echo "========正在检查账户密码策略========"
Check_User_Poli=`grep -E "^minlen|^minclass" /etc/security/pwquality.conf |wc -l`
cp /etc/security/pwquality.conf{,_bak$Date_Time}
if [ $Check_User_Poli -lt 2 ];then
echo -e "\033[31;40m当前系统未对账户密码复杂度及密码最小长度设置\033[0m"
sed -i '$iminlen = 12' /etc/security/pwquality.conf && echo -e "\033[32;40m 修改成功 \033[0m" || echo -e "\033[31;40m 修改失败 \033[0m"
sed -i '$iminclass = 4' /etc/security/pwquality.conf && echo -e "\033[32;40m 修改成功 \033[0m" || echo -e "\033[31;40m 修改失败 \033[0m"
else
PACLS=`grep -E "^minclass" /etc/security/pwquality.conf | awk -F"=| " '{ print $NF }'`
PALEN=`grep -E "^minlen" /etc/security/pwquality.conf | awk -F"=| " '{ print $NF }'`
if [ $PACLS -eq 4 ];then
echo -e "\033[32;40m密码负责度为$PACLS种类型，符合标准\033[0m";
else
echo -e "\033[31;40m密码负责度为$PACLS种类型，不符合标准\033[0m";
sed -i 's/^minclass.*/minclass = 4/' /etc/login.defs && echo -e "\033[32;40m 修改成功 \033[0m" || echo -e "\033[31;40m 修改失败 \033[0m"
fi
if [ $PALEN -ge 12 ];then
echo -e "\033[32;40m密码长度为$PALEN位，符合标准\033[0m";
else
echo -e "\033[31;40m密码长度为$PALEN位，不符合标准\033[0m";
sed -i 's/^minlen.*/minlen = 12/' /etc/login.defs && echo -e "\033[32;40m 修改成功 \033[0m" || echo -e "\033[31;40m 修改失败 \033[0m"
fi
fi
}用户认证失败次数设置
function Check_Auth_Failed(){
echo "========正在检查用户登陆认证失败次数========"
Check_Auth_Failsystem=`grep pam_faillock.so /etc/pam.d/system-auth | wc -l`
Check_Auth_Failpasswd=`grep pam_faillock.so /etc/pam.d/password-auth | wc -l`
cp /etc/pam.d/system-auth{,_bak$Date_Time}
cp /etc/pam.d/password-auth{,_bak$Date_Time}
if [ $Check_Auth_Failsystem -ge 3 ];then
if [ $Check_Auth_Failpasswd -ge 3 ];then
echo -e "\033[32;40m 用户登陆连续认证失败锁定策略设置成功，符合标准 \033[0m"
else
echo -e "\033[31;40m 用户登陆连续认证失败锁定策略设置不完全，不符合标准 \033[0m"
fi
else
echo -e "\033[31;40m 用户登陆连续认证失败锁定策略设置不正确，不符合标准 \033[0m"
sed -i '/auth required pam_env.so/i auth required pam_faillock.so preauth audit silent deny=5 unlock_time=900' /etc/pam.d/system-auth
sed -i '/auth required pam_deny.so/a auth [default=die] pam_faillock.so authfail audit deny=5 unlock_time=900' /etc/pam.d/system-auth
sed -i '/account required pam_unix.so/i account required pam_faillock.so' /etc/pam.d/system-auth
sed -i '/auth required pam_env.so/i auth required pam_faillock.so preauth audit silent deny=5 unlock_time=900' /etc/pam.d/password-auth
sed -i '/auth required pam_deny.so/a auth [default=die] pam_faillock.so authfail audit deny=5 unlock_time=900' /etc/pam.d/password-auth
sed -i '/account required pam_unix.so/i account required pam_faillock.so' /etc/pam.d/password-auth
fi
}账号密码过期设置
设置定时任务，可以每天自己执行判断，如果快到期会发邮件告警，及时修改，防止过期导致crontab任务不可使用
#!/bin/bash
#定义时间变量，用于告警发送
check_time=`date +"%Y-%m-%d %H:%M:%S"`
#日志位置
log=${HOME}/user-info.log
user_name=`whoami`
end_year=` chage -l ${user_name} | head -2| tail -1 | awk -F: '{print $2}'| awk -F',' '{print $2}'| awk '{print $1}'`
if [ "${end_year}" == "" ];then
echo "99999"
exit 0
fi
end_mounth=`chage -l ${user_name} | head -2| tail -1 | awk -F: '{print $2}'| awk -F',' '{print $1}'| awk '{print $1}'`
case ${end_mounth} in
'Jan') end_mounth=1;;
'Feb') end_mounth=2;;
'Mar') end_mounth=3;;
'Apr') end_mounth=4;;
'May') end_mounth=5;;
'Jun') end_mounth=6;;
'Jul') end_mounth=7;;
'Aug') end_mounth=8;;
'Sep') end_mounth=9;;
'Oct') end_mounth=10;;
'Nov') end_mounth=11;;
'Dec') end_mounth=12;;
esac
end_day=`chage -l ${user_name} | head -2| tail -1 | awk -F: '{print $2}'| awk -F',' '{print $1}'| awk '{print $2}'`
end_date_s=`/bin/date -d "${end_year}"-"${end_mounth}"-"${end_day}" +%s`
star_date_s=`/bin/date +%s`
let diffday=(${end_date_s}-${star_date_s})/86400
echo ${diffday}
#过期时间判断，如果小于15天，开始发邮件
if [ ${diffday} -gt 15 ]
then
curl http://mail.ownit.top/send -H "Content-Type:application/json" -X POST -d '{"source" : "game","contacts" : ["1794748404@qq.com"],"subject" : "'" ${user_name} 账号过期警告"'","content" : "'" ${user_name} 账号过期警告 <br> ${user_name} 即将在 ${diffday} 后过期，请及时修改 <br> 注意: 账号密码过期后,用户的Crontab中的执行任务会失效 <br><br><br><br><br><br> "'"}'
echo " time: $check_time 账号 ${user_name} 即将 在 ${diffday} 天后 密码过期 " >> ${log}
else
echo " time: $check_time 账号 ${user_name} 还有 ${diffday} 天使用期 " >> ${log}
fi
