UVA1601 The Morning afther Halloween

题目大意

  w h (w, h <= 16)的网格有 n ( n <= 3) 个小写字母(代表鬼)其余的是‘#’(代表障碍格) 或 ‘ ’(代表空格。 要求把他们移动到对应的大写字母里。每步可以有多个鬼同时移动(均为上下左右4个移动方向之一), 但每步移动两个鬼不能占用同一个位置, 也不能在一步之内交换位置。输入保证空格联通,障碍联通,且在2 2子网格中至少有一个障碍格,并且最外面一层是障碍格。输入保证有解。

基本原理

  Bfs模拟三个小鬼到处乱走的状态即可。

优化

  1. 我们可以将带障碍的网格图更改为一张由节点和边组成的图,避免了搜索时对障碍的判断。
  2. 对于状态的判重,不要用stl的set$Olog n$解决,我们要想办法在$O(1)$的时间内判重。建图时图的节点的下标要离散化,不是其在网格图中的位置row * TotCol + col,而是新建出这个节点的序号。这样,由于位置最多有$(2^4)^2=2^8$,所以我们可以如此状态压缩:将第一个小人所在节点的编号|(第二个小人所在节点的编号<<8)|(第三个小人所在节点的编号<<16)。这样我们就可以用数组来判重了。
  3. 循环总是比递归快。进行状态转移时,不要递归每一个小人的位置。用循环枚举。对于人数<3的情况,将不用的人放到一个孤立点中即可。
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <queue>
#include <iostream>
#include <bitset>
#include <cstdarg>
using namespace std;

const int MAX_ROW = 20, MAX_COL = 16, MAX_ROLE = 3, MAX_EDGE = MAX_ROW * MAX_COL * 4, MAX_STATE = 20000000;
bool IsWall[MAX_ROW][MAX_COL];
int TotRole, TotRow, TotCol;
int Ans;
int Dist1[MAX_STATE], Dist2[MAX_STATE];

struct Node;
struct Edge;

struct Node
{
    Edge *Head;
}_nodes[MAX_ROW * MAX_COL];
int _vCount;

Node *_cord[MAX_ROW][MAX_COL];
Node *NewNode(int row, int col)
{
    return _cord[row][col] = _nodes + _vCount++;
}

struct Edge
{
    Node *To;
    Edge *Next;
}_edges[MAX_EDGE];
int _eCount;

void AddEdge(Node *from, Node *to)
{
    Edge *e = _edges + ++_eCount;
    e->To = to;
    e->Next = from->Head;
    from->Head = e;
}

struct State
{
    Node *Pos[MAX_ROLE];
    int Dist;

    void Clear()
    {
        memset(Pos, NULL, sizeof(Pos));
        Dist = 0;
    }

    State() { Clear(); }

    bool CanMove(Node **tos)
    {
        for (int i = 0; i < MAX_ROLE; i++)
            for (int j = i + 1; j < MAX_ROLE; j++)
            {
                if (tos[i] == Pos[j] && tos[j] == Pos[i])
                    return false;
                if (tos[i] == tos[j])
                    return false;
            }
        return true;
    }

    State GetMove(Node **tos)
    {
        State ans;
        for (int i = 0; i < MAX_ROLE; i++)
            ans.Pos[i] = tos[i];
        return ans;
    }
}Start, Target;
queue<State> q1, q2;

void ClearAll()
{
    memset(Dist1, -1, sizeof(Dist1));
    memset(Dist2, -1, sizeof(Dist2));
    while (!q1.empty())
        q1.pop();
    while (!q2.empty())
        q2.pop();
    Start.Clear();
    Target.Clear();
    memset(_nodes, 0, sizeof(_nodes));
    memset(_edges, 0, sizeof(_edges));
    memset(IsWall, 0, sizeof(IsWall));
    _eCount = 0;
    Ans = 0;
    _vCount = 3;
    Start.Pos[0] = _nodes, Start.Pos[1] = _nodes + 1, Start.Pos[2] = _nodes + 2;
    Target.Pos[0] = _nodes, Target.Pos[1] = _nodes + 1, Target.Pos[2] = _nodes + 2;
    memset(_cord, NULL, sizeof(_cord));
}

void BuildGraph()
{
    for (int row = 0; row < TotRow; row++)
        for (int col = 0; col < TotCol; col++)
            if (!IsWall[row][col] && !_cord[row][col])
                NewNode(row, col);
    for (int i = TotRole; i < MAX_ROLE; i++)
    {
        AddEdge(Start.Pos[i], Start.Pos[i]);
        AddEdge(Target.Pos[i], Target.Pos[i]);
    }
    const int Dir[4][2] = { { 1, 0 },{ 0, 1 },{ -1, 0 },{ 0, -1 } };
    for (int row = 0; row < TotRow; row++)
        for (int col = 0; col < TotCol; col++)
        {
            if (IsWall[row][col])
                continue;
            AddEdge(_cord[row][col], _cord[row][col]);
            for (int i = 0; i < 4; i++)
            {
                int row1 = row + Dir[i][0], col1 = col + Dir[i][1];
                if (row1 < 0 || row1 >= TotRow || col1 < 0 || col1 >= TotCol)
                    continue;
                if (IsWall[row1][col1])
                    continue;
                AddEdge(_cord[row][col], _cord[row1][col1]);
            }
        }
}

int State_int(State& S)
{
    int state = S.Pos[0] - _nodes | (S.Pos[1] - _nodes << 8) | (S.Pos[2] - _nodes << 16);
    return state;
}

void DoNext(State& cur,
    int *distIn, int *distOut,
    queue<State>& qIn)
{
    Node *tos[MAX_ROLE];
    for (Edge *e0 = cur.Pos[0]->Head; e0; e0 = e0->Next)
        for (Edge *e1 = cur.Pos[1]->Head; e1; e1 = e1->Next)
            for (Edge *e2 = cur.Pos[2]->Head; e2; e2 = e2->Next)
            {
                tos[0] = e0->To, tos[1] = e1->To, tos[2] = e2->To;
                if (!cur.CanMove(tos))
                    continue;
                State next = cur.GetMove(tos);
                next.Dist = cur.Dist + 1;
                int nextS = State_int(next);
                if (distIn[nextS] >= 0)
                    continue;
                distIn[nextS] = next.Dist;
                if (distOut[nextS] >= 0)
                {
                    Ans = next.Dist + distOut[nextS];
                    return;
                }
                qIn.push(next);
            }
}

int Bfs()
{
    Start.Dist = Target.Dist = 0;
    Dist1[State_int(Start)] = Dist2[State_int(Target)] = 0;
    q1.push(Start);
    q2.push(Target);
    while (true)
    {
        int curDist = q1.front().Dist;
        while (q1.front().Dist == curDist)
        {
            State cur = q1.front();
            q1.pop();
            DoNext(cur, Dist1, Dist2, q1);
            if (Ans)
                return Ans;
        }
        while (q2.front().Dist == curDist)
        {
            State cur = q2.front();
            q2.pop();
            DoNext(cur, Dist2, Dist1, q2);
            if (Ans)
                return Ans;
        }
    }
    return Ans;
}

int main()
{
    char s[MAX_COL + 5];
    while (scanf("%d%d%d
", &TotCol, &TotRow, &TotRole) && (TotRow || TotCol || TotRole))
    {
        ClearAll();
        for (int row = 0; row < TotRow; row++)
        {
            memset(s, 0, sizeof(s));
            fgets(s, sizeof(s), stdin);
            for (int col = 0; col < TotCol; col++)
            {
                char ch = s[col];
                if (ch == '#')
                    IsWall[row][col] = true;
                else if ('a' <= ch && ch <= 'c')
                    Start.Pos[ch - 'a'] = NewNode(row, col);
                else if ('A' <= ch && ch <= 'C')
                    Target.Pos[ch - 'A'] = NewNode(row, col);
            }
        }
        BuildGraph();
        printf("%d
", Bfs());
    }
    return 0;
}

  

原文地址:https://www.cnblogs.com/headboy2002/p/9734209.html