(Winform程序带源码) 弹出输入框和获取输入框的值

 弹出输入框和获取输入框的值:

        private void button1_Click(object sender, EventArgs e)
        {
            string returnValue = Microsoft.VisualBasic.Interaction.InputBox("输入修改值", "", "", 300, 300);
        }

 

原文地址:https://www.cnblogs.com/hcyblogs/p/6645100.html