【Leetcode_easy】844. Backspace String Compare

problem

844. Backspace String Compare

solution1:

class Solution {
public:
    bool backspaceCompare(string S, string T) {
        return backspace(S)==backspace(T);
    }
    string backspace(string str)
    {
        string res ="";
        for(auto ch:str)
        {
            if(ch=='#') 
            {
                if(!res.empty()) res.pop_back();
            }
            else res.push_back(ch);
        }
        return res;
    }
};

solution2:

class Solution {
public:
    bool backspaceCompare(string S, string T) {
        string s = "", t = "";
        for(auto ch:S) ch=='#' ? (s.empty()? void():s.pop_back()) : s.push_back(ch);//err...
        for(auto ch:T) ch=='#' ? (t.empty()? void():t.pop_back()) : t.push_back(ch);
        return s==t;
    }   
};

参考
1. Leetcode_easy_844. Backspace String Compare;

2. grandyang;

原文地址:https://www.cnblogs.com/happyamyhope/p/11214890.html