Python字典排序

1.利用key排序

d = {'d1':2, 'd2':4, 'd4':1,'d3':3,}
for k in sorted(d):
    print(k,d[k])

d1 2
d2 4
d3 3
d4 1

2.利用value排序:getitem

d = {'d1':2, 'd2':4, 'd4':1,'d3':3,}
for k in sorted(d,key=d.__getitem__):
    print(k,d[k])

d4 1
d1 2
d3 3
d2 4

反序: reverse=True

d = {'d1':2, 'd2':4, 'd4':1,'d3':3,}
for k in sorted(d,key=d.__getitem__,reverse=True):
    print(k,d[k])

d2 4
d3 3
d1 2
d4 1

3.对dict_items进行排序

d = {'d1':2, 'd2':4, 'd4':1,'d3':3,}
res = sorted(d.items(),key=lambda d:d[1],reverse=True)
print(res)

[('d2', 4), ('d3', 3), ('d1', 2), ('d4', 1)]

from: https://www.cnblogs.com/kilometerwine/p/9712329.html

原文地址:https://www.cnblogs.com/hankleo/p/11925115.html