JSON.parse解析报错解决方法

res = JSON.parse(result.replace(/ /g,"\n").replace(/ /g,"\r"));//转义
str_o = res.result;
str_n = str_o.replace(/\n/g," ");//解析后再转回来

摘自：https://blog.csdn.net/qq_31934975/article/details/78364301